#include<iostream>

using namespace std;

const int N = 100010, M = 1000010;

int n, m;
char p[N], s[M];
int ne[N];

int main(){
    cin >> n >> p + 1 >> m >> s + 1;
    //求next
    for(int i = 2, j = 0; i <= n; i ++){
        while(j && p[i] != p[j + 1]) j = ne[j];
        if(p[i] == p[j + 1]) j ++;
        ne[i] = j;
    }
    //匹配
    for(int i = 1, j = 0; i <= m; i ++){
        while(j && s[i] != p[j + 1]) j = ne[j];
        if(s[i] == p[j + 1]) j ++;
        if(j == n){
            printf("%d ", i - n);
            j = ne[j];
        }
    }
    return 0;
}